Răspuns:
-calculez moli si masa HCl care ,in reacyie cu Al, produce 1,25mol sare
6mol............2mol
2Al + 6HCl----> 2AlCl3 + 3H2
x.........................1,25mol
x= niu= 3,75mol HCl
miu,HCl= 36,5g/mol----> m= niuxmiu= 3,75x36,5g=136,875g
-calculez masa de solutie 50% care contine masa calculata de acid
c=mdx100/ms---> ms= 136,875x100/50g= 273,75g
Explicație: