Răspuns:
Explicație:
710 g Cl
react. cu Fe
g,moli Fe
g,moli produs de reactie
xg 710g yg
2Fe + 3 Cl2 = 2Fe Cl3
2 . 56 g 3 . 71g 2 .162,5g
x= 710 . 112 : 213 = 373,33 g Fe
n= m : M
n= 373,33g : 56g/moli = 6,66 moli Fe
y= 710 . 2 . 162,5 : 3 . 71 = 1 083,33 g FeCl3
n= 1083,33g : 162,5g/moli = 6,66 moli FeCl3
M FeCl3= 56 + 3.35,5= 162,5-------> 162,5g/moli