lungimea traseului:x
x=AB+BC+CD+DE+EF+FG+GH+HI+IJ+JK
[tex]x = 10 \sqrt{20} + 10 \sqrt{20} + 2 \sqrt{125} + 2 \sqrt{125} + 2 \sqrt{125} + 10 \sqrt{20} + 2 \sqrt{125} + 2\sqrt{125} + 2 \sqrt{125} + 2 \sqrt{125} [/tex]
[tex]x = 30 \sqrt{20} + 14 \sqrt{125} [/tex]
[tex] \sqrt{20} = 2 \sqrt{5} \\ \sqrt{125 } = 5 \sqrt{5} [/tex]
[tex]x = 30 \times 2 \sqrt{5} + 14 \times 5 \sqrt{5} \\ x = 60 \sqrt{5 } + 70 \sqrt{5} \\ x = 130 \sqrt{5} [/tex]
drumul are in total 130 rad 5 km.
