[tex]\it (\sqrt[3]{\it2})^{log_2 8}=(2^{\frac{1}{3}})^{log_2 2^3}=(2^{\frac{1}{3}})^3=2^{\frac{1}{3}\cdot3}=2\in\mathbb{N}[/tex]
buna !
rezolvarea in poza ツ
