d) {[ 2^99 : 2^98 +1}^43 : (3^3)^14 +1}^50 :(2^3)^33 +0 =
= {[2+1]^43 : 3^42 +1}^50 : 2^99 =
= (3^43 : 3^42 +1)^50 :2^99=
= (3+1)^50 :2^99=
=(2^2)^50 : 2^99=
=2^100 : 2^99 =2
f) [ (5^23)^4 :(5^3)^30 -23]^17 :(2^2)^8 +2^3=
=[5^92 : 5^90 -23]^17 : 2^16 +8=
= (5^2 - 23)^17 : 2^16 +8=
= (25-23)^17 : 2^16 +9=
= 2^17 : 2^16 +9 = 2+19 =11
