Răspuns:
Explicație pas cu pas:
[tex]-\frac{\Big{2\sqrt{2}} }{\Big3} + \frac{\Big{\sqrt{2}}}{\Big4} = \sqrt{2}*\Big( -\frac{\Big2}{\Big3} + \frac{\Big1}{\Big4}\Big) = \sqrt{2}*\frac{\Big{-8+3}}{\Big{12}} = -\frac{\Big{5\sqrt{2}}}{\Big{12}}[/tex]