Răspuns :
Răspuns:
41(1+2+3+....81)=41·(81·82)/2=41·3321=136161=369² → pp
√136161=369
[tex]\it 41\cdot(1+2+3+\ ...\ +81)=41\cdot\dfrac{81\cdot82}{2}=41\cdot81\cdot41=41^2\cdot9^2=\\ \\ \\ =(41\cdot9)^2=369^2[/tex]
Răspuns:
41(1+2+3+....81)=41·(81·82)/2=41·3321=136161=369² → pp
√136161=369
[tex]\it 41\cdot(1+2+3+\ ...\ +81)=41\cdot\dfrac{81\cdot82}{2}=41\cdot81\cdot41=41^2\cdot9^2=\\ \\ \\ =(41\cdot9)^2=369^2[/tex]