Răspuns :
Răspuns:
[tex] ({2}^{56} \times {2}^{10} ) \div ( {2}^{42} \times {2}^{31} ) = \\ {2}^{56 + 10} \div {2}^{42 + 31} = \\ {2}^{66} \div {2}^{73} = \\ {2}^{66 - 73} = \\ {2}^{ - 7} = \\ ( { \frac{1}{2} })^{7} = \frac{ {1}^{7} }{ {2}^{7} } = \\ \frac{1}{128} [/tex]