Răspuns:
miu, acetaldehida= 44g/mol
niu=m/miu= 132/44mol=3mol
1mol..................1mol..........1mol
CH3-CH2OH + O---> CH3CHO+ H2O
x............3mol
x=3molO
1mol................................................................................................3mol
K2Cr2O7 + 4H2SO4----> K2SO4+ Cr2(SO4)3 + 4H2O+ 3O
x..........................................................................................................3mol
x= 1mol K2Cr2O7
c,m= niu/V---> V= 1mol/1mol/L= 1L
Explicație: