Răspuns :
[tex] {25}^{8} = {( {5}^{2}) }^{8} = {5}^{16} [/tex]
[tex] {125}^{5} = {( {5}^{3}) }^{5} = {5}^{15} [/tex]
[tex] {5}^{16} \div {5}^{15} = {5}^{1} [/tex]
Explicație pas cu pas:
[tex] \bf 25^{8}: 125^{5} =\big(5^{2} \big)^{8}: \big(5^{3} \big)^{5} = [/tex]
[tex]\bf 5^{2\cdot8}: 5^{3\cdot5}= 5^{16}: 5^{15}= 5^{16-15} =\red{ \underline{5^{1}}}[/tex]