Răspuns :

102533id

Răspuns:

Explicație pas cu pas:

a) 2√50 - 3√32 + (√1800 )/3 =

= 2√(5²·2) - 3√(2⁴·2) + [√(2·2²·3²·5²)] /3 =

= 2·5·√2 - 3·2²·√2 + 2·3·5√2 / 3 =

= 10√2 - 27√2 + 10√2 = √2(10-27+10) =

= √2·(-7) = -7√2

b) 4√18 - 2√8 - √3(3√12-1) =

= 4√(3²·2) - 2√(2²·2) - 3√36 + √3 =

= 4·3·√2 - 2·2·√2 -3·6 +√3 =

= 12√2 - 4√2 - 18 +√3 =

= 8√2 - 18 + √3

Targoviste44id

[tex]\it a)\ \sqrt{50}-3\sqrt{32}+\dfrac{1}3}\sqrt{1800}=2\sqrt{25\cdot2}-3\sqrt{16\cdot2}+\dfrac{1}{3}\cdot\sqrt{900\cdot2}=\\ \\ \\ =10\sqrt2-12\sqrt2+10\sqrt2=20\sqrt2-12\sqrt2=8\sqrt2\\ \\ \\ b)\ 4\sqrt{18}-2\sqrt8-\sqrt3(3\sqrt{12}-1)=4\sqrt{9\cdot2}-2\sqrt{4\cdot2}-3\sqrt{36}+\sqrt3=\\ \\ \\ 12\sqrt2-4\sqrt2-18+\sqrt3=-18+8\sqrt2+\sqrt3[/tex]

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