Răspuns,explicație pas cu pas:
[tex]0,3x>1,2x*(1,4x+o)[/tex]
[tex]0,3x>1,2x*1,4x\\
0,3x>1,62^{2} [/tex]
[tex]\frac{3}{10} x-\frac{42}{25} x^{2} >0[/tex]
[tex]15x-84x^{2} >0\\
3x*(5-28x)>0[/tex]
[tex]x*(5-28x)>0[/tex]
[tex]\left \{ {{x>0} \atop {5-28x>0}} \right. \\\\\\left \{ {{x<0} \atop {5-28x<0}} \right. [/tex] fara ,,left,, , nu stiu ce s a intamplat aici,iarta-ma
[tex]\left \{ {{x>0} \atop {x<\frac{5}{28} }} \right. \\
\\
\left \{ {{x>\frac{5}{28} } \atop {x>0}} \right. [/tex]
dupa avem intersectia care ne da:
x∈[tex](0,\frac{5}{28)} [/tex]
