Răspuns :

Targoviste44id

[tex]\it d)\ 2x+2\geq x-3 \Rightarrow 2x-x\geq-3-2 \Rightarrow x\geq-5 \Rightarrow x\in[-5,\ \ \infty)\\ \\ b)\ x-4>2|_{+4} \Rightarrow x>6 \Rightarrow x\in(6,\ \ \infty)\\ \\ a)\ x<5 \Rightarrow x\in(-\infty,\ \ 5)[/tex]

Chris02Juniorid

Răspuns:

Explicație pas cu pas:

a) x ∈ {-∞, 5)

b) x > 6, x ∈ (6, +∞)

c) 3x ≤ 13, x ≤ 13/3 = 4 1/3 ⇒ x ∈ (-∞, 4 1/3]

d) x ≥ -5, x ∈ [-5, +∞)

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