Răspuns:
1.
a)
[tex]6 \sqrt{2} = \sqrt{ {6}^{2} \times 2} = \sqrt{72} [/tex]
[tex]8 \sqrt{3} = \sqrt{ {8}^{2} \times 3} = \sqrt{192} [/tex]
[tex]9 \sqrt{2} = \sqrt{ {9}^{2} \times 2 } = \sqrt{162} [/tex]
[tex]5 \sqrt{6} = \sqrt{ {5}^{2} \times 6 } = \sqrt{150} [/tex]
[tex]7 \sqrt{3} = \sqrt{ {7}^{2} \times 3 } = \sqrt{147} [/tex]
[tex]4 \sqrt{7} = \sqrt{ {4}^{2} \times 7} = \sqrt{112} [/tex]
[tex] - 10 \sqrt{3} = - \sqrt{ {10}^{2} \times 3 } = - \sqrt{300} [/tex]
[tex] - 12 \sqrt{5} = - \sqrt{ {12}^{2} \times 5 } = - \sqrt{720} [/tex]
b)
[tex] - \frac{3}{4} \sqrt{3} = - \sqrt{ (\frac{3}{4} )^{2} \times 3 } = - \sqrt{ \frac{27}{16} } [/tex]
[tex] - \frac{4}{9} \sqrt{5} = - \sqrt{ \frac{80}{81} } [/tex]
[tex] - \frac{2}{3} \sqrt{7} = - \sqrt{ \frac{28}{9} } [/tex]
[tex] - 5 \sqrt{7} = - \sqrt{175} [/tex]
[tex] - 6 \sqrt{5} = - \sqrt{180} [/tex]
[tex] - 4 \sqrt{2} = - \sqrt{32} [/tex]
[tex]7 \sqrt{10} = \sqrt{490} [/tex]
c)
[tex]5 \sqrt{14} = \sqrt{350} [/tex]
[tex] - 3 \sqrt{15} = - \sqrt{135} [/tex]
[tex] - 8 \sqrt{6} = - \sqrt{384} [/tex]
[tex]17 \sqrt{3} = \sqrt{867} [/tex]
[tex] - 9 \sqrt{10} = - \sqrt{810} [/tex]
[tex]12 \sqrt{6} = \sqrt{864} [/tex]
[tex] - 6 \sqrt{7} = - \sqrt{252} [/tex]
[tex] - 14 \sqrt{2} = - \sqrt{392} [/tex]
d)
[tex]12 \sqrt{7} = \sqrt{1008} [/tex]
[tex]13 \sqrt{5} = \sqrt{845} [/tex]
[tex] - 11 \sqrt{6} = - \sqrt{726} [/tex]
[tex] - \frac{8}{5} \sqrt{3} = - \sqrt{ \frac{192}{25} } [/tex]
[tex] - \frac{5}{12} \sqrt{2} = - \sqrt{ \frac{50}{144} } = - \sqrt{ \frac{25}{72} } [/tex]
[tex]18 \sqrt{3} = \sqrt{972} [/tex]
[tex] - 15 \sqrt{2} = - \sqrt{450} [/tex]
2.
a) E foarte simplu, urmează exemplul pe care ți l-am dat!
b) La fel.
c)
[tex] - 11 \sqrt{6} = - \sqrt{726} [/tex]
[tex] - 5 \sqrt{3} = - \sqrt{75} [/tex]
[tex] - \frac{7}{2} \sqrt{2} = - \sqrt{ \frac{98}{4} } = - \sqrt{ \frac{49}{2} } [/tex]
d)
[tex] \frac{3}{7} \sqrt{3} = \sqrt{ \frac{27}{49} } [/tex]
[tex]0.(3) \sqrt{21} = \sqrt{ \frac{21}{9} } = \sqrt{ \frac{7}{3} } [/tex]
[tex]0.(1) \sqrt{6} = \sqrt{ \frac{6}{81} } = \sqrt{ \frac{2}{27} } [/tex]
[tex] - 0.(6) \sqrt{15} = - \sqrt{ \frac{60}{9} } = - \sqrt{ \frac{20}{3} } [/tex]
[tex]0.(4) \sqrt{63} = \sqrt{ \frac{1008}{81} } = \sqrt{ \frac{112}{9} } [/tex]
