Răspuns:
[tex] log( \frac{1}{2} \times \frac{2}{3} \times .... \times \frac{99}{100} ) = log( \frac{1}{100} ) = log( {10}^{ - 2} ) = - 2[/tex]
[tex] log_{3}( \frac{2}{1} \times \frac{3}{2} \times ... \times \frac{9}{8} ) = log_{3}( \frac{9}{1} ) = log_{3}( {3}^{2} ) = 2[/tex]
