Răspuns :

Kitty200704id

[tex]a = {2}^{36} = {2}^{3 \times 12} = {( {2}^{3}) }^{12} = {8}^{12} [/tex]

[tex]b = {3}^{24} = {3}^{2 \times 12} = {( {3}^{2}) }^{12} = {9}^{12} [/tex]

[tex] {8}^{12} < {9}^{12} [/tex]

[tex]a < b[/tex]

Răspuns:

Explicație pas cu pas:

[tex]\bf a = 2^{36}= \big(2^{6}\big)^{6} = \purple{ \boxed{\bf ~64^{6~}}}[/tex]

[tex]\bf b = 3^{24}= \big(3^{4}\big)^{6} = \red{ \boxed{\bf ~81^{6~}}}[/tex]

[tex]\bf \pink{ \underline{\bf ~81^{6}~>~ 64^{6}}}[/tex]

[tex]\bf \pink{ \bf ~b~>~ a}[/tex]

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