Răspuns :

Răspuns:

Explicație pas cu pas:

[tex]\bf 3\sqrt{8} -\sqrt{50} +2\sqrt{18} =[/tex]

[tex]\bf 3\sqrt{2^{3}} -\sqrt{2\cdot5^{2}} +2\sqrt{2\cdot3^{2}} =[/tex]

[tex]\bf 3\cdot 2\sqrt{2} -5\sqrt{2} +2\cdot3\sqrt{2} =[/tex]

[tex]\bf 6\sqrt{2} -5\sqrt{2} +6\sqrt{2} =[/tex]

[tex]\bf 12\sqrt{2} -5\sqrt{2} =\green{\underline{~7\sqrt{2}~}}[/tex]

__________________

[tex]\bf \sqrt{12} -\sqrt{27} +2\sqrt{75} =[/tex]

[tex]\bf \sqrt{2^{2}\cdot3} -\sqrt{3^{3}} +2\sqrt{3\cdot5^{2}} =[/tex]

[tex]\bf 2\sqrt{3} -3\sqrt{3} +2\cdot5\sqrt{3} =[/tex]

[tex]\bf 2\sqrt{3} -3\sqrt{3} +10\sqrt{3} =[/tex]

[tex]\bf 12\sqrt{3} -3\sqrt{3}=\blue{\underline{~9\sqrt{3}~}}[/tex]

[tex]==pav38==[/tex]  

[tex]\it 3\sqrt8-\sqrt{50}+2\sqrt{18}=\sqrt2(3\sqrt4-\sqrt{25}+2\sqrt9)=\sqrt2(6-5+6)=7\sqrt2\\ \\ \\ \sqrt{12}-\sqrt{27}-2\sqrt{75}=\sqrt3(\sqrt4-\sqrt9-2\sqrt{25})=\sqrt3(2-3-10)=-11\sqrt3[/tex]