Răspuns:
Explicație pas cu pas:
a)
A = {1, 2, 4, 8, 16}
B = {2⁰, 2¹ , 2² , 2³ , 2⁴} = {1, 2, 4, 8, 16}
A = B
b)
A = {8, 9, 10, 11, 12, ..., 38, 39 }
40 ≤ 5y < 201
8 ≤ y < 40,2
B = {8, 9, 10, 11, 12, ..., 38, 39, 40}
A ≠ B
c)
[tex](10^2)^{10x} : (10^3*10^6*10^9)^x = 10000\\10^{20x} : (10^{18})^x = 10^4\\10^{20x} : 10^{18x} = 10^4\\10^{20x-18x} = 10^4\\10^{2x} = 10^4\\2x = 4\\x=2\\[/tex]
A = {2}
[tex]x + 2x + 3x + ... + 10x = 110\\x*(1 + 2 + 3 +... + 10) = 110\\x*\frac{10*11}{2} = 110\\x * 55 = 110\\x = \frac{110}{55} \\x = 2[/tex]
B = {2}
A = B
