Răspuns :

Kitty200704id

[tex] \sqrt{48} + \sqrt{75} + \sqrt{27} - \sqrt{300 } = \\ 4 \sqrt{3} + 5 \sqrt{3} + 3 \sqrt{3} - 10 \sqrt{3} = \\ 9 \sqrt{3} + 3 \sqrt{3} - 10 \sqrt{3} = \\ 12 \sqrt{3} - 10 \sqrt{3} = \\ = 2 \sqrt{3} [/tex]

Targoviste44id

[tex]\it \sqrt{48}+\sqrt{75}+\sqrt{27}-\sqrt{300}=\sqrt3(\sqrt{16}+\sqrt{25}+\sqrt{9}-\sqrt{100})=\\ \\ =\sqrt3(4+5+3-10)=2\sqrt{3}[/tex]

ID Alte intrebari