Răspuns:
[tex]b = \frac{2}{ \sqrt{2} } + \frac{1}{ \sqrt{3} + \sqrt{2} } + \frac{3}{ \sqrt{3} } \\ \frac{2 \sqrt{2} }{2} + \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} + \frac{3 \sqrt{3} }{3} = \\ 6 \sqrt{2} + 6( \sqrt{3} + \sqrt{2} ) + 6 \sqrt{3} = \\ 6\sqrt{2} + 6 \sqrt{3} + 6 \sqrt{2} + 6 \sqrt{3} = 12( \sqrt{3 } + \sqrt{2} ) \\ a)3 \sqrt{2} = \sqrt{ {3}^{2} + 2 } = \sqrt{11} \\ b)3 \sqrt{2} \times 12( \sqrt{3} + \sqrt{2} ) = \\ 36 \sqrt{6} + 36 \sqrt{4} = 36 \sqrt{6} + 72 = 36( \sqrt{6} + 2)[/tex]
