Răspuns :

Misionicaid

Răspuns:

[tex] \frac{2x +1}{3} = \frac{x - 3}{6} - \frac{x + 3}{4} + \frac{2x + 1}{12} \\ 4(2x + 1) = 2(x - 3) - 3(x + 3) + 2x + 1 \\ 8x + 4 = 2x - 6 - 3x - 9+ 2x + 1 \\ 8x - 2x + 3x - 2x = - 4 - 6 - 9+ 1 \\ 7x = - 18\\ x = \frac{-18}{7} [/tex]

PutereDinuid

[tex]\frac{2x+1}{3}=\frac{x-3}{6}-\frac{x+3}{4}+\frac{2x+1}{12}=\frac{2(x-3)}{12}-\frac{3(x+3)}{12}+\frac{2x+1}{12} \\\\ \frac{2x+1}{3}=\frac{2x-6-3x-9+2x+1}{12} \\ \frac{x-14}{4}=2x+1 \\ x-14=4(2x+1)=8x+4 \\ 14=-7x+4=4-7x \\ 7x=4-14=-18 \\ \boxed{x=-\frac{18}{7}}[/tex]

ID Alte intrebari