Răspuns:
1. 195g Zn; 294g H₂SO₄
2. 112g Fe
Explicație:
1.
M(H₂SO₄) = 2 × A(H) + A(S) + 4 × A(O) = 2 × 1 + 32 + 4 × 16 = 98 g/mol
M(H₂) = 2 × A(H) = 2 × 1 = 2 g/mol
x y 6g
Zn + H₂SO₄ → ZnSO₄ + H₂↑
65g 98g 2g
x = 65 × 6 : 2 = 195g Zn
y = 98 × 6 : 2 = 294g H₂SO₄
2.
M(FeCl₂) = A(Fe) + 2 × A(Cl) = 56 + 2 × 35,5 = 127 g/mol
x 254g
Fe + 2HCl → FeCl₂ + H₂↑
56g 127g
x = 56 × 254 : 127 = 112g Fe
-Mihai
