Răspuns :
cos=cateta alaturata/ipotenuza
cos C=AC/BC -> BC=AC/cosC=6/0.6=10 cm
Aplicam teorema lui Pitagora;AB^2+AC^2=BC^2-> AB=8 cm
P=AB+BC+AC=8+10+6=24 cm
cos C=AC/BC -> BC=AC/cosC=6/0.6=10 cm
Aplicam teorema lui Pitagora;AB^2+AC^2=BC^2-> AB=8 cm
P=AB+BC+AC=8+10+6=24 cm
cosC=3/5
3/5=6/BC
BC=30/3
BC=10
[tex]AC ^{2}+AB ^{2} =BC ^{2} [/tex]
36+[tex]AB ^{2} [/tex]=100
[tex]AB ^{2} =100-36[/tex]
[tex]AB ^{2} =64[/tex]
AB=8
P=6+8+10
=24
3/5=6/BC
BC=30/3
BC=10
[tex]AC ^{2}+AB ^{2} =BC ^{2} [/tex]
36+[tex]AB ^{2} [/tex]=100
[tex]AB ^{2} =100-36[/tex]
[tex]AB ^{2} =64[/tex]
AB=8
P=6+8+10
=24