[tex]\sqrt{27} + \sqrt{147} = \sqrt{48} + \sqrt{n}\\
\sqrt{27} = 3 \sqrt{3}\\
\sqrt{147} = 7 \sqrt{3}\\
\sqrt{48} = 4 \sqrt{3}\\
\sqrt{27} + \sqrt{147} - \sqrt{48}= \sqrt{n}\\
3 \sqrt{3} + 7 \sqrt{3} - 4 \sqrt{3} = \sqrt{n}\\
6 \sqrt{3} = \sqrt{n} => \\
\sqrt{n} = \sqrt{108} = > n =108[/tex]
