Răspuns:
miu,Na2SO4.xH2O= [(2x23+32+4x16)gNa2SO4 + 18x,gH2O]/mol
(142+18x)g SARE..............32gS
100g........................................9,93g
3200=9,93(142+18x)---------> x=10
miu.Na2SO4.10H2O=(142+180)g/mol=322g/mol
c=mdx100/ms-=md, sare neutrax100/(m,sare Glauber+m,apa adaugata)
md= cxms/100=15x16,1/100kg=2,415kg Na2SO4
322g Na2SO4.10H2O........142gNa2SO4
X..............................................2,415g
x=5,476g Na2SO4.10H2O
Explicație: