[tex]\frac{3}{5}=\frac{2x-7}{9} => (2x-7)*5=3*9 => 10x-35=27\\10x=27+35 => 10x=62 => x=\frac{62}{10} \\\\\frac{3x+4}{7}=\frac{11}{5} => (3x+4)*5=11*7 => 15x+20=77\\15x=77-20 => 15x=57 => x=\frac{57}{15} \\\\\frac{5x+1}{2}=\frac{4}{3} => (5x+1)*3=2*4 =>15x+3=8\\15x=8-3 => 15x=5 => x=\frac{5}{15} => x=\frac{1}{3}[/tex]
