Răspuns:
Explicație pas cu pas:
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xyyz divizibil cu 5 ; x ≠ y ≠ z
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x+y+y+z = aa
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aa poate fi 11 , 22 sau 33 (prea mare)
z poate fi 0 sau 5
y = 9 => x+18+0 = 22 => x = 4 => 4990
x + 18 +5 = 33 => x prea mare
y = 8 => x+16+0 = 22 => x = 6 => 6880
x +16+5 = 22 => x = 1 => 1885
y = 7 => x+14+0 = 22 => x = 8 => 8770
x+14+5 = 22 => x = 3 => 3775
y = 6 => x+12+0 = 22 => x prea mare
x+12+5 = 22 => x = 5 , nu convine
y = 5 => x+10+0 = 11 => x = 1 => 1550
y = 4 => x+8+0 = 11 => x = 3 => 3440
x +8+5 = 22 => x = 9 => 9445
y = 3 => x+6+0 = 11 => x = 5 => 5330
x+6+5 = 11 => x prea mic
y = 2 => x+4+0 = 11 => x = 7 => 7220
x+4+5 = 11 => x = 2 , nu convine
y = 1 => x+2+0 = 11 => x = 9 => 9110
x+2+5 = 11 => x = 4 => 4115
y = 0 => x+0+5 = 11 => x = 6 => 6005