Răspuns:
m,amidon= 100x25/100kg=25kg..teoretic
m,amidon= 25x80/100kg=20kg ...practic
miu,amidon=162n,Kg/kmol
miu glucoza= 180 kg/kmol
(C6H10O5)n+ nH2O-----> nC6H12O6
162n ,Kg..............................180n Kg
20kg.........................................x
x=22,22 kg glucoza
C6H12O6+ 2[Ag(NH3)2]OH--> C6H12O7+2Ag + 4NH3 + H2O
180Kg................................................................2X108kg
22,22kg...........................................................................x
x= 26,66kg oglinda de argint
Explicație: