Răspuns:
Explicație pas cu pas:
a = (√3+√3²+√3³+.....+√3¹⁰)/(33+11√3)
a = (√3+3+3√3+3²+9√3+3³+27√3+3⁴+81√3+243):(33+11√3)
a = (3+9+27+81+243+√3+3√3+9√3+27√3+81√3):(33+11√3)
a = (363+121√3):(33+11√3)
a = [121(3+√3)] : [11(3+√3)]
a = 121:11 => a = 11 ∈ N
