a = CH3-CH2-Cl
b = CH2=CH2
c = CH3-CH2-OH
d = CH3-COOH
e = CH3-COOCH2-CH3
80% ........................................ 44 kg
100% ...................................... m = 55 kg ester obtinut teoretic
n moli 55 kg
C2H6 --> ...... --> CH3COOC2H5
1 88
=> n = 1x55/88 = 0,625 kmoli
PV = nRT => V = nRT/P
= 0,625x0,082x(273+77)/3,5
= 5,125 m3 => D.
