Răspuns:
a)
[tex]=[1+\frac{1}{2} +\frac{1}{4} +\frac{1}{8} ]*\frac{1}{1+2+4+8} =[/tex]
[tex]=\frac{8+4+2+1}{8} *\frac{1}{1+2+4+8} = \frac{1}{8}[/tex]
b)
[tex]=\frac{3^{13} }{2^{13} } *\frac{3^{8} }{2^{8} } *\frac{2^{19} }{3^{19} } -2=[/tex]
[tex]=\frac{3^{2} }{2^{2} } -2 =[/tex]
[tex]=\frac{3^{2} -2^{3} }{2^{2} } =\frac{9-8}{4} =\frac{1}{4}[/tex]
Explicație pas cu pas:
