Răspuns:
a)
[tex]\sqrt{9*2} (\sqrt{36*3} -2\sqrt{16*3} )-\sqrt{4*3} (\sqrt{144*2} -\sqrt{36*2} ) = 3\sqrt{2} (6\sqrt{3} -8\sqrt{3} )-2\sqrt{3} (12\sqrt{2} -6\sqrt{2} )=3\sqrt{2} *(-2\sqrt{3} )-2\sqrt{3} *6\sqrt{2} =-6\sqrt{6} -12\sqrt{6} =-18\sqrt{6}[/tex]
b)
[tex]\sqrt{4*3} (3\sqrt{25*2} -\sqrt{81*2} )-\sqrt{9*2} (\sqrt{144*3} -\sqrt{64*3} )=2\sqrt{3} (15\sqrt{2} -9\sqrt{2} )-3\sqrt{2} (12\sqrt{3} -8\sqrt{3} )=2\sqrt{3} *6\sqrt{2} -3\sqrt{2}*4\sqrt{3} =12\sqrt{6} -12\sqrt{6} =0[/tex]
Explicație pas cu pas:
