Calculaţi masele molare pentru substanțele:
M K2 O =
M Fe2 S3 =
M Na2 SO4 =
M hidroxid de Ba =
M sulfat de Ga =

2. Calculaţi:

1 molFe2 S3 = ? g
7 moli K2 O = ? g
500g Na2 SO4 = ? moli
300g Mg CO3 = ?moli

Calculaţi:
3moli H2 O= ? particule
5moli H2SO4 = ? particule
Se dau masele atomice: Na-23, Ba-137, Cr-52,Fe-56, O-16, S-32, Al-27, K-39, H-1, Li-7, Mg-24, C-12, Ga-70

Question

a fost răspuns

Răspuns :

Pokju8888id Pokju8888id · Answer 1

Răspuns:

Explicație:

1.

MK2O= 2.39 + 16= 94------> 94g/moli

MFe2S3= 2.56 + 3.32= 208-------> 208g/moli

MNa2 SO4= 2.23 + 32 + 4.16= 142------> 142g/moli

MBa(OH)2= 137 + 2.16 +2=171-----> 171g/moli

MGa2(SO4)3 = 2.70 + 3.32 + 12.16=428------> 428g/moli

2.

MFe2S3=208-----> 208g/moli

m= n . M

m= 1mol . 208g/moli= 208g

m= 7moli . 94g/moli = 658 g K2O

n=m : M

n= 500g : 142g/moli= 3,52 moli Na2SO4

MMgCO3 =24 + 12 + 3.16 = 84----> 84g/moli

n= 300g : 84g/moli=3,57 moli MgCO3

3.

1mol H2O---------6,022.10²³molecule H2O-------3 . 6,022.10²³atomi

3moli----------------------x-----------------------------------------y

x= 3 . 6,022.10²³ = 18,066 .10²³molecule H2O

y= 3 . 3 . 6,022.10²³ = 54,198 .10²³atomi

1mol H2SO4----------6,022.10²³molecule -------7 . 6,022.10²³atomi

5 moli-------------------------x---------------------------------------y

x= 5 . 6,022.10²³molecule=30,110.10²³molecule H2SO4

y= 5 . 7 . 6,022.10²³=210,77.10²³atomi