Explicație pas cu pas:
Aflăm ipotenuza BC cu teorema lui Pitagora
BC^=AB^+AC^
BC^=6^+8^
BC^=36+64
BC^=100
BC=radical din 100
BC=10
sin u =AC/BC=6/10=3/5
sin v =AB/BC= 8/10=4/5
cos u= AB/ BC=8/10=4/5
cos v=AC/BC=6/10=3/5
tg u=AC/AB=6/8=3/4
tg v=AB/AC=8/6=4/3
ctg u=AB/AC=8/6=4/3
ctg v= AC/AB=6/8=3/4
