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Targoviste44id

[tex]\it f(x)=(a-3)x+5\\ \\ A(-2,\ \sqrt3)\in Gf \Rightarrow f(-2)=\sqrt3 \Rightarrow (a-3)\cdot(-2)+5=\sqrt3 \Rightarrow\ \\ \\ \Rightarrow -2a+6+5=\sqrt3 \Rightarrow 6+5-\sqrt3=2a \Rightarrow a=\dfrac{11-\sqrt3}{2}[/tex]

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