Răspuns:
Explicație:
80g Ca(OH)2 , p= 70%
react. cu HCl
masa de sare obt.
-se afla masa pura de Ca(OH)2
mp= p . mi : 100
mp=70 . 80 : 100=56 g Ca(OH)2 pur
56g xg
Ca(OH)2 +2 HCl= CaCl2 + 2H2O
74g 111g
x= 56 . 111 : 74=84 g CaCl2
n= 84g : 111g/moli=0,76 moli Ca(OH)2
MCa(OH)2= 40 + 2.16 + 2=74------> 74g/moli
MCaCL2= 40 + 2.35,5= 111------> 111g/moli