Răspuns:
Notam cu x si y numerele
x-y = 130 (1)
x:3y=2 rest 5
Aplicam teorema impartirii cu rest (D=C*I+r)
x=2*3y+5 => x=6y+5 (2)
Din (1) si (2) => [tex]\left \{ {{x-y=130} \atop {x=6y+5}} \right. [/tex] <=>[tex]\left \{ {{6y+5-y=130} \atop {x=6y+5}} \right. [/tex]<=>[tex]\left \{ {{5y=125 \atop {x=6y+5} \right. [/tex] <=>[tex]\left \{ {{y=25} \atop {x=6y+5}} \right. [/tex] <=>[tex]\left \{ {{y=25} \atop {x=155}} \right. [/tex]
