Răspuns: [tex]\red{\LARGE\boxed{\bf 21,3}}[/tex]
Explicație pas cu pas:
[tex]\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[100\cdot 0,01 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{5}:0,1\bigg)\bigg]\Bigg\}-\dfrac{13-1}{9} : \dfrac{1}{9} =[/tex]
[tex]\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{5}:\dfrac{1}{10}\bigg)\bigg]\Bigg\}-\dfrac{12}{9} \cdot \dfrac{9}{1} =[/tex]
[tex]\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{\not5}\cdot\dfrac{\not10}{1}\bigg)\bigg]\Bigg\}-\dfrac{12}{\not9} \cdot \dfrac{\not9}{1} =[/tex]
[tex]\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-6\cdot 2\bigg)\bigg]\Bigg\}-12 = [/tex]
[tex]\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-12\bigg)\bigg]\Bigg\}-12 = [/tex]
[tex]\large\bf 1,5\cdot\Bigg[3+3,2\cdot\bigg(1 + \dfrac{5}{\not2} \cdot \not2\bigg)\Bigg]-12 = [/tex]
[tex]\large\bf 1,5\cdot\Bigg[3+3,2\cdot\bigg(1 + 5\bigg)\Bigg]-12 = [/tex]
[tex]\large\bf 1,5\cdot\bigg(3+3,2\cdot 6\bigg)-12 = [/tex]
[tex]\large\bf 1,5\cdot\bigg(3+19,2\bigg)-12 = [/tex]
[tex]\large\bf 1,5\cdot 22,2 -12 = [/tex]
[tex]\large\bf 33,3 -12 = [/tex]
[tex]\red{\Large\boxed{\bf 21,3}}[/tex]
[tex]\text{PS: Daca esti pe telefon gliseza spre stanga pentru a vedea rezolvarea}[/tex]
#copaceibrainly
