[tex]1.2(13) = \frac{1213 - 12}{990} = \frac{1201}{990} [/tex]
[tex]0.(81) = \frac{81}{99} = \frac{9}{11} [/tex]
2)a)43:4=10,75
b)8,07:1,2=6,725
3)0,144:0,12+1,69:1,3-6,25:2,5=
1,2+1,3-2,5=2,5-2,5=0
4)[2,(3)×0,3+7,(1)×4,5] :1,2
(23-2/9×3/10+71-7/9×45/10):1,2
(21/9×3/10+64/9×45/10):1,2
(63/90+2880/90):1,2
(2954/90):1,2
1477/45:1,2
1477/45:12/10
1477/45×5/6
1477/54
5)-23,7+(-22,5)+(-21,6)/3=462,3/3=154,1
6)Înalțimea Ralucăi: x
x:1,2=1,62
1,2=6/5
==>>
x:6/5=1,62
x×5/6=1,62
x=6/5×1,62
1,62=81/50
x=6/5×81/50
x=243/125
x=1,944(înalțimea Ralucăi)
sper că te-am ajutat!
