Răspuns:
Explicație:
CLORURA DE POTASIU
52,35 % K KCl 47,65 % Cl
M= 39 + 35,5= 74,5 -----> 74,5g/moli
r.a.= 1 : 1 r.m.= 39 : 35
n=m: M
m= n . M
m= 2moli .74,5g/moli=149 g KCl
compozitie procentuala
MKCl= 74,5------> 74,5g/moli
74,5g KCl-------39 g K----------35,5g Cl
100g KCl------------x--------------------y
x= 100.39 : 74,5=52,35% K
y= 100. 35,5 : 74,5=47,65% Cl
