[tex]\it 3a+b=44\ \ \ \ \ \ (1)\\ \\ \\ \{a,\ \ b\}\ d.\ p.\ \{2,\ \ 5\} \Rightarrow \dfrac{^{3)}a}{\ \ 2}=\dfrac{b}{5} \Rightarrow \dfrac{3a}{6}=\dfrac{b}{5}=\dfrac{3a+b}{6+5}\ \stackrel{(1)}{=}\ \dfrac{44}{11}=4\\ \\ \\ \dfrac{b}{5}=4 \Rightarrow b=5\cdot4 = 20\ \ \ \ \ \ (2)\\ \\ \\ (1),\ (2) \Rightarrow 3a+20=44|_{-20} \Rightarrow 3a=24|_{;3} \Rightarrow a=8[/tex]
Numerele cerute sunt: a = 8, b = 20.
