Răspuns:
Salut
a)√3(x-2)+2√3(x+1)=6√3
√3x-2√3+2√3x+2√3=6√3
√3x+2√3x=6√3
3√3x=6√3
x=2.
b)2√3(x+2)+4√6=3√3(2x+2√2)-2√3
2√3x+4√3+4√6=6√3x+6√6-2√3
-4√3x=2√6-6√3
x=- 2(√6-3√3)/4√3
x=- √6-3√3/2√3
x=9-√18/6
x=9-3√2/6
x=3(3-√2)/6
x=3-√2/2.
c)2x(√3+√2)-√2(3+2x)=√3(x+√2)
2√3x-3√2=√3x+√6
2√3x-√3x=√6+3√2
√3x=√6+3√2
x=√6+3√2/√3
x=(√6+3√2)√3/√3
x=√18+3√6/√3
x=3√2+3√6/3
x=3(√2+√6)/3
x=√2+√3.
==evergreen==
