Răspuns:
[tex] \frac{1}{2} < \frac{3}{2} \\ \frac{2}{5} < \frac{2}{3} deoarece \: aducandule \: la \: aceasi \: numitori \: e \: \frac{6}{15} < \frac{10}{15} \\ \frac{4}{1} > \frac{11}{3} deorece \: \frac{12}{3} > \frac{11}{3} \\ \frac{11}{25} < \frac{3}{2} [/tex]
