Vs= 1500 mL(cm3) , p= 1,15 g/cm3 , c%= 63%
p = ms/Vs => ms = pxVs = 1725 g sol.
c% = mdx100/ms => md = msxc/100
= 1725x63/100 = 1086,75 g HNO3
V L b moli
4NH3 + 5O2 --> 4NO + 6H2O
4x22,4 4
b moli a moli
2NO + O2 --> 2NO2
2 2
a moli 1086,75 g
3NO2 + H2O --> 2HNO3 + NO
3 2x63
a = 3x1086,75/2x63 = 25,875
b = a
=> V = 4x22,4x25,875/4 = 579,6 L NH3 in c.n.