Răspuns:
x ∈ [-3/2 ; -1) ∪(0 ; 1)
Explicație pas cu pas:
{ 2x+3 ≥ 0 => x ≥ -3/2 => x ∈ [-3/2 ; +∞)
{ x(x-1)/(x+1) < 0 => x ∈ (-∞ ; -1) ∪ (0 ; 1) => x ∈ [-3/2 ; -1) ∪(0 ; 1)
x I -∞ -3/2 -1 0 1 +∞
x I ----------------------------0+++++++++++++
x-1 I------------------------------------0+++++++++
x+1 I-----------------------0++++++++++++++++
x(x-1) I++++++++++++++++++0----0++++++++
x(x-1)/(x+1) I------------------------I+++0----0++++++++
#copaceibrainly
