Răspuns:
a) sin(2x)=m/2
daca -1 ≤ m/2 ≤ 1 ⇔ -2 ≤ m ≤ 2 ⇔ m ∈ [-2, 2] ⇒ 2x = arcsin(m/2) ⇒ x = 1/2·arcsin(m/2)
daca m ∈ (-∞,-2) ∪ (2,+∞) - ecuatia nu are solutii
b) √2cos(x)=m ⇔cos(x)= m/√2
daca -1 ≤ m/√2 ≤ 1 ⇔ -√2 ≤ m ≤ √2 ⇔ m ∈ [-√2, √2] ⇒ x = arccos(m/√2)
daca m ∈ (-∞,-√2) ∪ (√2,+∞) - ecuatia nu are solutii
c) tg(πx) = 1/m
m ≠ 0 ⇒ x = 1/π·arctg(1/m)
m = 0 - ecuatia nu are solutii
