Răspuns:
niuCO2=m/miu=0,792/44mol= 0,018molCo2
niuC=niuCO2=0,018mol
dar niuC =6
0,54g compus........0,018molC
X.......................................6molC
x=miu= 180g/mol
niuH2O=m/miu=0,324/18mol=0,018molH2O
niuH=2niuH2O= 0,036mol
0,54g compus............0,036molH
180g(1mol)...........................x
x= 12molH
Compusul poate fi C6H12Ox
m,O= 180-mC-mH
mO= 96g
niuO= 96/16mol= 6mol
C6H12O6
16x ,gO= 18-
Explicație:
