Răspuns:
Explicație pas cu pas: 1. a) [tex]A(x) + B(x) = \frac{x+2}{3x^{2} } +\frac{x-2}{3x^{2} } =\frac{2x}{3x^{2} } =\frac{2}{x}[/tex]
b)[tex]A(x)-B(x)= \frac{x+2}{3x^{2} } -\frac{x-2}{3x^{2} } = \frac{x+2}{3x^{2} } +\frac{-x+2}{3x^{2} }=\frac{4}{3x^{2} }[/tex]
2. a) [tex]B(x): A(x)=\frac{4x^{5} }{x+4} :\frac{x10x^{2}}{x+4}=\frac{4x^{5} }{10x^{2} } =\frac{4}{10} *\frac{x^{5} }{x^{2} } =\frac{2}{5} *x^{5-2} =\frac{2x^{3} }{5}[/tex]
b) [tex]A(x)^{2} =\frac{10(x^{2} )^{2} }{x+4} =\frac{10x^{2*2} }{x+4} =\frac{10x^{4} }{x+4}[/tex]
