din problema obs. ca avem in exces H2 dar deducem ca reactia nu este completa si prin urmare avem si C3H6 netransformat
a moli a a
C3H6 + H2 --> C3H8
1 1 1
b moli b
H2 --------------> H2 exces
1 1
c moli c
C3H6 ----------> C3H6 netransformat
1 1
initial: a+c/a+b = 1/3
=> 3a+3c = a+b => b = 2a+3c
final amestec gazos: a+b+c = a+2a+3c+c = 3a+4c
d(aer) = M.mediu.amestec.gazos/M.mediu.aer
=> M.mediu.amestec.gazos = d(aer)xM.mediu.aer
= 0,519x28,9 = 15 g/mol
M.mediu = fractie.C3H8xM.C3H8 + fractie.H2xM.H2 + fractie.C3H6xM.C3H6
M.C3H8 = 44 g/mol
M.H2 = 2 g/mol
M.C3H6 = 42 g/mol
=> fractia = nr.moli.component/nr.moli.amestec
=> fractie.C3H8 = a/3a+4c
=> fractie.H2 = b/3a+4c
=> fractie.C3H6 = c/3a+4c
=> 15(3a+4c) = 44a + 2b + 42c
=> 45a + 60c = 44a+ 2b + 42c
=> a + 18c = 2b
=> a+18c = 2(2a+3c)
=> a+18c = 4a+6c => 3a = 12c => a = 4c
n% = ax100/a+c = 400c/5c = 80%
