Răspuns:
b)
[tex] \sqrt{15} \div \sqrt{5} - \sqrt{6} \div \sqrt{2} = [/tex]
[tex] \sqrt{3} - \sqrt{3} = [/tex]
=> 0
d)
[tex] \sqrt{35} \div ( - 7) - \sqrt{10} \div \sqrt{2} = [/tex]
[tex] - \sqrt{35} \div \sqrt{7} - \sqrt{10} \div \sqrt{2} = [/tex]
[tex] - \sqrt{5} - \sqrt{10} \div \sqrt{2} = [/tex]
[tex] - \sqrt{5} - \sqrt{5} = [/tex]
(Se reduc termenii)
=>
[tex] - 2 \sqrt{5} [/tex]
f)
[tex](9 \sqrt{10} ) \div \sqrt{2} - (8 \sqrt{15}) \div ( - \sqrt{3} ) = [/tex]
[tex]9 \sqrt{5} - 8 \sqrt{15} \div ( - \sqrt{3} ) = [/tex]
(cele 2 minusuri se transformă în plus Pt. Ca "-" cu "-" = "+")
[tex]9 \sqrt{5} + 8 \sqrt{15} \div \sqrt{3} = [/tex]
[tex]9 \sqrt{5} + 8 \sqrt{5} = [/tex]
=>
[tex]17 \sqrt{5} [/tex]
h)
[tex]( - 9 \sqrt{14} ) \div ( - 3 \sqrt{2} ) - ( - 4 \sqrt{21} ) \div ( - \sqrt{3} ) = [/tex]
[tex]3 \sqrt{7} - ( - 4 \sqrt{21} ) \div ( - \sqrt{3} ) = [/tex]
[tex]3 \sqrt{7} + 4 \sqrt{21} \div ( - \sqrt{3} ) = [/tex]
[tex]3 \sqrt{7} - 4 \sqrt{21} \div \sqrt{3} = [/tex]
[tex]3 \sqrt{7} - 4 \sqrt{7} = [/tex]
=>
[tex] - \sqrt{7} [/tex]
